Find the hcf of 10216 and 828 by Lemma class 10 cbse board
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Find the hcf of 10216 and 828 by Lemma class 10 cbse board
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Step-by-step explanation:
using Euclids division lemma.
a=bq+r; 0<_ r<b.
here a=10216 and b=828
so, 10216=828× 12+280
828=280×2+268
280=268×1+12
268=12×22+4
12=4×3+0.
HCF is 4.
I hope you got it ..
it's simple.....