find the HCF of 510,and92
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Here is your answer :
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Euclid Lemma :
92 ) 510 ( 5
460
------
50)92 (1
50
----
42)50 (1
42
----
8)42 (50
40
-----
2 )8 (4
8
----
0
510 = (92×5) + 50
92 = ( 50 × 1) + 42
50 = ( 42×1) + 8
42 = (8×5) + 2
8 = ( 2×4) + 0
Therefore, HCF = 2
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