find the LCM and HCF of {x^2y^3 , x^3y } and verify it also .
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The numbers are x² × y³ , x³ × y
LCM = x³ × y³
HCF = x² × y
Verification :
LCM × HCF = Product of two numbers
LHS :
LCM × HCF = x³ × y³ × x² × y
= x^{5} × y⁴
RHS :
Product of two numbers = = x² × y³ × x³ × y
= x^{5} × y⁴
Therefore ,
LHS = RHS
Hence verified....
Hope it helps
x^2y^3 , x^3y
HCF = x^2y
LCM = x^3y^3
VERIFICATION:-
HCF × LCM = a × b
[Where a = x^2y^3 & b = x^3y]
x^2y × x^3y^3 = x^2y^3 × x^3y
x^5y^4 = x^5y^4
Therefore,
LHS = RHS
#Verified
Hope my answer helps you :)
Regards,
Shobana