Find the least number which when divided by 6, 15 and 18 leaves remainder 5 in each case.
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Find the least number which when divided by 6, 15 and 18 leaves remainder 5 in each case.
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Verified answer
[tex]\huge{\underline{\mathtt{\blue{A}\red{N}\pink{S}\green{W}\purple{E}\orange{R}}}}[/tex]
Step-by-step explanation:
6 = 2 × 3
15 = 3 × 5
18 = 2 × 3 × 3
L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5
L.C.M (6, 15 and 18) = 90
Therefore, the required number = 90+5 = 95
As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.
As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.
Answer:
[tex]\huge\star\underline{\orange{❥︎a}\mathfrak\blue{n}\mathfrak\purple{S}\mathbb\pink{wer}}\star\:[/tex]
95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.