find the least number which when divided separately by 15 , 20 , 36 and 40 leaves 3 as a remainder in each case ??
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find the least number which when divided separately by 15 , 20 , 36 and 40 leaves 3 as a remainder in each case ??
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Answer:
May be 43 leaves 3 as a remainder in each case
Answer:
number,n=363
Step-by-step explanation:
n=L.C.M(15,20,36,40) + 3
L.C.M of 15,20,36 and 40
15=3x5
20=2x2x5
36=2x2x3x3
40=2x2x2x5
L.C.M=2x2x2x3x3x5
L.C.M=360
n=L.C.M(15,20,36,40) + 3
n=360+3
n=363