find the least number which when divides 36,56and91leaves the same remainder 7 in each case
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find the least number which when divides 36,56and91leaves the same remainder 7 in each case
find the least number which when divides 36,56and91leaves the same remainder 7 in each case
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Answer:
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Answer:
29×7×2×3
Step-by-step explanation:
first minus 7 from all numbers
so 29,49,84 are left
then take lcm of all of them
lcm=29×7×7×2×2×3
=29×7×2×3
=1218
hope u understood...
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