Find the length of the base of a triangle whose area is 440m2 and altitude is 11m •
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Find the length of the base of a triangle whose area is 440m2 and altitude is 11m •
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Question :
Find the length of the base of a triangle whose area is 440m² and altitude is 11m .
Answer :
[tex]\bf\pink{Given:}[/tex]
[tex]\bf\pink{To\:find:}[/tex]
Explanation :
[tex]\sf\purple{ Area\:of\:triangle = \dfrac{1}{2}\times b\times h }[/tex]
[tex]\\ \longrightarrow\sf{ 440 = \dfrax{1}{2}\times b\times 11}[/tex]
[tex]\\ \longrightarrow\sf{ 440\times 2 = 11b}[/tex]
[tex]\\ \longrightarrow\sf{ 880 = 11b}[/tex]
[tex]\\ \longrightarrow\sf{b = \dfrac{880}{11}}[/tex]
[tex]\\ \longrightarrow\sf{b = 80}[/tex]
Therefore the base is 80 m .