find the letterd angle in this figure
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Answer:
Step-by-step explanation:
EDA=63 DEGREES (AS AF=AD)
EAD=180-63-63=54 DEGREES
CAB=EAD=54 DEGREES(VERTICALLY OPPOSITE)
CBA=X(CA=CB)
NOW,
X+X+54=180
2X=126
X=63 DEGREES
PLZ PLZ MARK BRAINLIEST
Hey there!
Answer:
63°
Step-by-step explanation:
Given,
∠E = 63°
Here, ΔDAE is isosceles Δ. (2 sides are equal)
∠E = ∠D (base ∠s of isosceles Δ are equal)
∠E + ∠D + ∠DAE = 180° ( angle sum property)
63° + 63° + ∠DAE = 180°
∠DAE = 180 - 63 - 63
∠DAE = 54°
Now,
∠BAC = ∠DAE = 54° (vertically opp. ∠s)
Again,
ΔBAC is isosceles Δ. (2 sides are equal)
∠C = ∠E = x° (base ∠s of isosceles Δ are equal)
Then,
∠B + ∠C + ∠BAC = 180° (angle sum property)
x + x +54 = 180
2x = 180 - 54
x = 126 / 2
x = 63°
Hope It helps You!