Find the mass of water lifted by a pump of 0.5hp to a height of 10m in 60sec
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Verified answer
228.36 kg is the required answer.
GIVEN:
TO FIND:
Mass of water lifted, m
FORMULAE:
SOLUTION:
STEP 1:
STEP 2:
f = ma
Here a = g , acceleration due to gravity.
g = 9.8 m/s²
f = m × 9.8
f = 9.8 × m
STEP 3:
work = force × displacement
Here displacement refers to the height.
work = force × height
= 9.8 × m × 10
work done = 98 × m
STEP 4:
POWER = WORK / TIME
ANSWER:
Mass of the water lifted is 228.36 kg .
DIRECT FORMULA:
Power , p = (mgh) / t
IMPORTANT POINTS:
Answer:
hi
228.36 kg is the required answer.
GIVEN:
Power, p = 0.5 hp
Height, h = 10 m
Time, t = 60 sec
TO FIND:
Mass of water lifted, m
FORMULAE:
Power = work done / time
work done, w = force × distance
According to Newton's second law of motion, force, f = ma
SOLUTION:
STEP 1:
SI unit of power is watt.
1 horse power = 746 watt
0.5 horse power = 0.5 × 746 watt
p = 746/2
Power, p = 373 watt.
STEP 2:
f = ma
Here a = g , acceleration due to gravity.
g = 9.8 m/s²
f = m × 9.8
f = 9.8 × m
STEP 3:
work = force × displacement
Here displacement refers to the height.
work = force × height
= 9.8 × m × 10
work done = 98 × m
STEP 4:
POWER = WORK / TIME
\begin{gathered}373 = \frac{98 \times m}{60} \\ \\ 373 \times 60 = 98 \times m \\ \\ m = \frac{373 \times 60}{98} \\ \\ m = \frac{22380}{98} \\ \\ m = 228.36 \: kg\end{gathered}
373=
60
98×m
373×60=98×m
m=
98
373×60
m=
98
22380
m=228.36kg
ANSWER:
Mass of the water lifted is 228.36 kg .
DIRECT FORMULA:
Power , p = (mgh) / t
IMPORTANT POINTS:
Power is defined as the rate of doing work.
It is a scalar quantity. It has magnitude alone. It does not have direction.
Power is also equal to dot product of force and velocity.
Work is a form of energy. It is a scalar quantity.
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