Find the mean of:
(1) All the factors of 36.
(2) First five multiples of 3.
(3) First 10 even natural numbers.
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Find the mean of:
(1) All the factors of 36.
(2) First five multiples of 3.
(3) First 10 even natural numbers.
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Answer:
1. 10.11
2. 6,9,12,15,18
3. 2,4,6,8,10,12,14,16,18,20
(1) factors of 36
1,2,3,4,6,9,12,18,36
mean = sum of observations divided by no of observations
mean=( 1 +2 +3 +4 +6 +9 +12 +18 +36)/ 9
mean =91/9
mean =10.11
(2) The first five multiples of 3 are 3,6,9,12,15
mean of ungrouped data is sum of the data divided by no of numbers.
Mean= 3+6+9+12+15/5 = 45/5 =9
(3) first 10 even natural numbers are 2,4,6,8,10,12,14,16,18,20
so mean = 2+4+6+8+10+12+14+16+18+20/10 = 110/10 = 11
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