Find the measure of an angel, if six times it's complement is 120° less than twice it's supplement.
Needed with full explanation. Don't copy from net otherwise I will report it.
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Find the measure of an angel, if six times it's complement is 120° less than twice it's supplement.
Needed with full explanation. Don't copy from net otherwise I will report it.
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Answer:
let angle be x
complement 90−x
supplement 180−x
6(90−x)=2(180−x)−12 {Given}
540−6x=360−2x−12
180−12 = 4x
x=42
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Step-by-step explanation:
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Correct Question:
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AnswEr:
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⋆ Let the angle be x.
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⋆ whose Complement = 90 - x
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⋆ whose Supplement = 180 - x
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★ According to question,
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Six times complement of angle is 12° less than twice it's supplement.
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[tex]:\implies\sf 6(90^\circ - x) = 2(180^\circ - x) - 12^\circ[/tex]
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[tex]:\implies\sf 540 - 6x = 360 - 2x - 12[/tex]
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[tex]:\implies\sf 540 - 6x = 348 - 2x[/tex]
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[tex]:\implies\sf 540 - 348 = -2x + 6x[/tex]
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[tex]:\implies\sf 192 = 4x[/tex]
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[tex]:\implies\sf x = \cancel{ \dfrac{192}{4}}[/tex]
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[tex]:\implies\bf \red{x = 48^\circ}[/tex]
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[tex]\therefore[/tex] The measure of angle is 48°