find the point on the x axis which is equidistant from ( 2, - 5 )and (- 2,9)
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find the point on the x axis which is equidistant from ( 2, - 5 )and (- 2,9)
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Answer:
Step-by-step explanation:
Distance formula ✓(x2-x1)^2+(y2-y1)^2
O - (x,0) ; P - (2,-5) ; Q - (-2,9)
Putting values
PO=QO
Equating
LHS PO=✓29+x^2-4
RHS QO=✓85+x^2+4x
Square both sides
And you'll get the answer
8x=-56
x= -7
Step-by-step explanation:
let the point be (a,0)
as it is equidistant from given points so,
so the points are (-7,0)
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