Find the point on y-axis which is equidistant from P(2,-5) and Q(-2,9).
Share
Find the point on y-axis which is equidistant from P(2,-5) and Q(-2,9).
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Correct option is
A
(−7,0)
Since point on x−axis, then coordinate of the point is (x,0).
According to the question this point (x,0) is equidistant from the points (2,−5) and (−2,9).
That is, distance from (x,0) and (2,−5) = distance from (x,0) and (−2,9).
(2−x)
2
+(−5−0)
2
=
(−2−x)
2
+(9−0)
2
⇒(2−x)
2
+(−5)
2
=(−2−x)
2
+(9)
2
⇒4−4x+x
2
+25=4+4x+4+81
⇒8x=25−81
⇒8x=−56
⇒x=−7
So, point is (−7,0
Step-by-step explanation:
Please vote me