find the PRINCIPAL SOLUTION of cos 3theta=sin 2theta
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Answer:
Hi There!!!
Step-by-step explanation:
Now we have
cos 3A=sin 2A ( now write cos 3A as sin (pi/2-3A)
sin (90-3A) = sin (2A)
now using the general solution formula
5A=npi+(-1)^n pi/2
On simplification A = pi/10(2n + (-1) ^ n )
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