find the quadritic polynomial sum of whose zeroes is 8 and their product is 12. hence find the zeroes of polynomial
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find the quadritic polynomial sum of whose zeroes is 8 and their product is 12. hence find the zeroes of polynomial
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Verified answer
Hi friend,the polynomial will be
→x²-(sum of zeros)x+product of zeros
→x²-8x+12 is the required polynomial
now, x²-8x+12
→x²-6x-2x+12
→x(x-6)-2(x-6)
→(x-2)(x-6)
so the zeros are 2 and 6
I hope this will help u :)
Verified answer
Hey there !!Sum of zeroes = 8
Product of zeroes = 12
Quadratic polynomial :-
x²-(sum of zeros)x+product of zeros
x²- 8x+12 -----> Required Polynomial !!
Now , Let us find their zeroes !!
For this we have to split the middle term !
x²- 6x-2x+12 -----> Splitting the middle term
x(x-6)-2(x-6)
= [ x - 2 ] [ x - 6 ]
x = 2 , x = 6
Hence ,
the zeros are 2 and 6