find the radius of the circle if the circumference of the circle is equal to the perimeter of the square which is equal to 154 cm
thnx yug
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find the radius of the circle if the circumference of the circle is equal to the perimeter of the square which is equal to 154 cm
thnx yug
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According to question:-
✠ Given that:-
✠ To find:-
✠ Formula used:-
[tex]\large \underline{\boxed{\sf{ \red{\implies2\pi r = circumference_{circle}}}}}[/tex]
Where,
Solution:-
[tex]\large\underline{\sf{ \implies2\pi r = 154 {cm}}}[/tex]
[tex]\large\underline{\sf{ \implies2 \times \frac{22}{7} \times r = 154cm }}[/tex]
[tex]\large\underline{\sf{ \implies \frac{44}{7} \times r = 154 {cm}}}[/tex]
[tex]\large\underline{\sf{ \implies r = \frac{154 {cm} \times 7}{44} }}[/tex]
[tex]\large\underline{ \boxed{\sf{ \red{\maltese\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: r = 24.5cm}}}}[/tex]
______________________________________
Additional information!!
[tex]\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \quad \footnotesize\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered} \end{gathered}
FormulasofAreas:−
⋆Square=(side)
2
⋆Rectangle=Length×Breadth
⋆Triangle=
2
1
×Breadth×Height
⋆Scalene△=
s(s−a)(s−b)(s−c)
⋆Rhombus=
2
1
×d
1
×d
2
⋆Rhombus=
2
1
d
4a
2
−d
2
⋆Parallelogram=Breadth×Height
⋆Trapezium=
2
1
(a+b)×Height
⋆EquilateralTriangle=
4
3
(side)
2
[/tex]
Verified answer
Answer:
this is your answer
Explanation:
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