find the ratio of the distances travelled by the freely falling body in 1st, 3rd and 5th seconds
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find the ratio of the distances travelled by the freely falling body in 1st, 3rd and 5th seconds
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S= u+ 0.5 a(2n-1)
This is the formula for distance travelled by a body at nth second.
a=g (for falling bodies)
S1 = 0.5g*1
S2 = 0.5g*3
S3= 0.5 g*5
Ratio is = 1:3:5
Hope this helps