Find the remainder when x^3-px^2+6x-p divided by x-p
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
[tex]\star{\mathbb{\underline{ANSWER:}}}[/tex]
[tex] let \: p(x) = {x}^{3} - p{x}^{2} + 6x - p [/tex]
[tex] Divisor \: = x – p[/tex]
[tex] Zero \:of \: x – p = p[/tex]
[tex]{By \:remainder \:theorem,}[/tex]
[tex]If \:p(x) \:is \:divided \:by \:(x – p), \:then \:the \:remainder \:is \:p(p)[/tex]
[tex] p ( p) = {p}^{3} - p ({p})^{2}+ 6 (p) -p [/tex]
[tex]={p}^{3}-{p}^{3}+6p- p [/tex]
[tex] = 6p - p [/tex]
[tex] =5p [/tex]
Answer:
Step-by-step explanation:
Jsksjsjwjwjw