Find the side of a square whose area is same as the area of a rhombus with diagonals 27cm 24cm long
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Find the side of a square whose area is same as the area of a rhombus with diagonals 27cm 24cm long
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Step-by-step explanation:
we know that area of square = area of rhombus
so,
area of rhombus = diagonal 1 * diagonal 2
= 27 * 24
= 648cm^2
since, perimeter of square = 4s
648 = 4s
648/4
=162
Hope this answer helps you
Answer:
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Step-by-step explanation:
Given :
Diagonals of rhombus are:
d1 = 27cm. d2 = 24cm
Area of rhombus = 1/2*d1*d2
= 1/2 *27 * 24
= 324 cm^2
According to question
Area of square = Area of rhombus
324cm^2 = 324cm^
Area of square = S * S
324 = S^2
√324 = S
18cm = Side of a square
(Hope this helps u .........)