find the slope of the line segment joining the points p(3.5,2.5)q(1.5,6)
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find the slope of the line segment joining the points p(3.5,2.5)q(1.5,6)
find the slope of the line segment joining the points p(3.5,2.5)q(1.5,6)
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Answer:
SEE
Step-by-step explanation:
Perpendicular bisector = Cuts at mid point, and is perpendicular
First find the mid point
x coordinate = 1+4 / 2 = 2.5
y coordinate = 5+6 / 2 = 5.5
Mid point = (2.5, 5.5)
Then find the slope of the bisector :
Slope of the given line = (5-6) / (1-4) = 1/3
Slope of given line multiplied by slope of bisector = -1
Slope of bisector = -1 / (1/3)
= -3
Use the point slope form to find the bisector's formula :
-3 = (5.5 - y) / (2.5 - x)
-7.5 + 3x = 5.5 - y
3x + y - 13 = 0
Transform the formula into slope-intercept form
3x + y - 13 = 0
y = -3x + 13
Because slope-intercept form is y = mx + c, where m is the slope and c is the y-intercept
Therefore the perpendicular bisector cuts the y-axis at (0,13)
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