Find the smallest 4-digit number which is divisible by 18, 24 and 32
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Find the smallest 4-digit number which is divisible by 18, 24 and 32
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Answer:
I think 1000 is the right answer for this question
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Answer:
Step-by-step explanation:
Largest 4 digit number= 9999
H.C.F. of 18, 24 and 32
18= 2×3×3
24=2×2×2×3
32=2×2×2×2×2
∴ H.C.F. = 2
∴ 9999÷2 gives the remainder 1
∴9999-1
=9998
The number 9998 is the required numbered.
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