Find the smallest number of 5 digits which is exactly divisible by 15, 24, 40.
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smallest number of five digit =10000
on dividing 10000 by 120 we get remainder 40
Now add (120-40) =80 to the number to make it a number of five digit
required answer will be (10000+80)=10080
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Answer:
First find the LCM if 15,24,40
120 smallest 5 digit number = 10,000 ÷ 120
40
120-40 =80
10,000 + 80
= 10,080