find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively
Share
find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Step-by-step explanation:
Answer Expert Verified
Given that the smallest number when divided by 28 and 32 leaves remainder 8 and 12 respectively. 28 - 8 = 20 and 32 - 12 = 20 are divisible by the required numbers. Therefore the required number will be 20 less than the LCM of 28 and 32. = 224.