find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32 respectively . please answer with explanation clearly .....
Share
find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32 respectively . please answer with explanation clearly .....
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
when 28 is divided by the number then it will remainder 8 . so the completely divisible number is 28-8=20
and when 32 divided by the number then it will remainder 12 so the completely divisible number os 32-12=20 .
there the number which will leave remainder 8 and 12 when divided by 28 and 32 is 20.
let the number be x
x = lcm of 28 and 32 - hcf of 28-8 and 32-12
x = (lcm of 28 and 32) - 20
x = 224-20
(hcf and lcm explanation is in the attachment )
So x = 204
please mark as BRAINLIEST