Find the smallest number which on being decreased by 3, is completely divisible by 24, 36 and 40.
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Find the smallest number which on being decreased by 3, is completely divisible by 24, 36 and 40.
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Answer:
L.C.M. of 18, 36, 32 and 27
= 2 × 2 × 3 × 3 × 3 × 8 = 864
∴ required number = 864 + 3 = 867