Find the sum of 28th terms of an arithmetic progression whose nth term is given by 7 – 3n.
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Find the sum of 28th terms of an arithmetic progression whose nth term is given by 7 – 3n.
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Answer: -1022
Step-by-step explanation:
Take sum of the nth term after this you will get S= 7n - 3n(n+1)/2
Put n=28 you will get -1022.