find the sum of all natural numbers lying between 100 & 500,which are divisible by 8.
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d = 8
an = 496
a + (n-1) d = 496
104 + (n-1) 8 = 496
(n-1) 8 = 496 - 104
(n-1) 8 = 392
n - 1 = 392/8
n - 1 = 49
n = 50
Sn = n/2 [2a + (n-1) d]
S50 = 50/2 [2 x 104 + (50-1) 8]
S50 = 25 [208 + (49) 8]
S50 = 25 [208 + 392]
S50 = 25 [600]
S50 = 15000
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d = 8
an = 496
a + (n-1) d = 496
104 + (n-1) 8 = 496
(n-1) 8 = 496 - 104
(n-1) 8 = 392
n - 1 = 392/8
n - 1 = 49
n = 50
Sn = n/2 [2a + (n-1) d]
S50 = 50/2 [2 x 104 + (50-1) 8]
S50 = 25 [208 + (49) 8]
S50 = 25 [208 + 392]
S50 = 25 [600]
S50 = 15000