Find the sum of all the numbers that can be formed with the digits 2, 3, 4, 5 taken
all at a time.
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Find the sum of all the numbers that can be formed with the digits 2, 3, 4, 5 taken
all at a time.
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Answer:
Thus, the average number in each digit position will be (2+3+4+5)/4 = 14/4 = 7/2. There are 24 permutations. So we get a sum of (24*7/2) = 84 in each position, which means the total is 84+840+8400+84000 = 93324. ... ways to arrange the four numbers with that digit fixed.