find the sum of first 10 multiples of 6
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Answer:
Answer is 330.
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Answer:
330
Step-by-step explanation:
first 10 multiples
that is from 6 to 60
let a be first term and d be the difference
a=6 d=6
tn(last term)=60
applying formula
tn=a+(n-1)d
60=6+(n-1)6
54/6=n-1
10=n
now let's find sum
sn=n/2[ a +tn]
=5[66]
=330
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