Find the sum of first 100 even natural
numbers.
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Find the sum of first 100 even natural
numbers.
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Answer: 10100
Step-by-step explanation:
The even Natural numbers are 2,4,6,8,10..............
As it forms an AP whose first term a = 2 , common difference d =2
Given in question n =100
Now as we know sum of n terms of an AP is
Therefore
=50(4+99*2)
= 50(202)
=10100
Therefore the sum of first 100 even natural numbers is 10100