find the sum of integers between hundred and 200 that are divisible by 9
PLZ find using AP formulae
CORRECT AND DETAILED ANSWER WILL BE MARKED AS BRAINLIEST
Share
find the sum of integers between hundred and 200 that are divisible by 9
PLZ find using AP formulae
CORRECT AND DETAILED ANSWER WILL BE MARKED AS BRAINLIEST
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Step-by-step explanation:
The sum of integers between 100 and 200 that are divisible by 6 is 2550.
Step-by-step explanation:
First no. between 100 and 200 that is divisible by 6 is 102
The last no. between 100 and 200 that is divisible by 6 is 198
Now the numbers between 100 and 200 that is divisible by 6:
102,102+6,102+6+6 ,....
So, it forma an AP
a = first term = 102
d = common difference = 6
Formula of nth term =
Sum of n terms =
Substitute n =17
Hence the sum of integers between 100 and 200 that are divisible by 6 is 2550.
Between 100 and 200, the first multiple of 9 is 108 and the last multiple of 9 is 198.
Now, we know, the consecutive multiples of a number x are always in AP with common difference(d) x.
According to the given conditions,
We know, aₙ = a₁ + (n - 1)d
⇒198 = 108 + (n - 1)9
⇒90 = 9n - 9
⇒99 = 9n
⇒n = 99/9
⇒n = 11
We also know :-
Where, n is the number of terms
Now, sum of the 11 terms :-