find the sum of last 10 terms of an ap 8 10 12...126
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find the sum of last 10 terms of an ap 8 10 12...126
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Given AP,
8, 10, 12....... 126
Here,
On reversing the AP,
126, 124....... 8
Here,
we need to find the sum of first 10 terms,
S = n/2{(2a + (n - 1)d}
s10 = 10/2 { 2(126) + (10-1)-2 }
= 5{252 + 9(-2)
= 5{252 - 18}
= 5{234}
= 1270
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