Find the sum of the zeroes the polynomial
6x²+12+5
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6x²+11x+5
= 6x²+6x+5x+5
= 6x(x+1)+5(x+1)
= (x+1)(6x+5)
Zeroes: x+1 = 0
x = -1
6x+5 = 0
x = -5/6
Sum of the zeroes
= -1+(-5/6)
= -1-5/6
= -6-5/6
= -11/6
Step-by-step explanation:
sum of the roots = -b/ a
= -12/6
then the value is -2
Hope it may helps u
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