Find the three numbers in GP whose sup is 21 and whose product is 216
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Find the three numbers in GP whose sup is 21 and whose product is 216
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Answer:
the three number are 12 ,6 and 3 if we add then it becomes 21 and multiply then it become 216.
total number which have the sum of 21 and product of 216 = 3
then 216 ÷ 3 =72
therefore and the double of 3 is equal to 6 and then 72 divide 6=12
now 12+6+3=21
and 12×6×3=216.
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