Find the total surface area of a closed cylinder whose radius is 14 cm and height is 8 cm.
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Find the total surface area of a closed cylinder whose radius is 14 cm and height is 8 cm.
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Step-by-step explanation:
Given, radius r=14 cm, height h=8 cm
Total surface area of cylinder =2πr(h+r) sq.units
=2×
7
22
×14(8+14)
=2×
7
22
×14×22
=1936 sq.cm.
Answer:
Given :-
To Find :-
Solution :-
Given :
[tex]\mapsto \bf Radius_{(Cylinder)} =\: 14\: cm\\[/tex]
[tex]\mapsto \bf Height_{(Cylinder)} =\: 8\: cm\\[/tex]
According to the question by using the formula we get,
[tex]\implies \sf\boxed{\bold{T.S.A._{(Cylinder)} =\: 2{\pi}r(r + h)}}\\[/tex]
where,
So, by putting those values we get,
[tex]\implies \sf T.S.A._{(Cylinder)} =\: 2 \times \dfrac{22}{7} \times 14(14 + 8)\\[/tex]
[tex]\implies \sf T.S.A._{(Cylinder)} =\: \dfrac{2 \times 22}{7} \times 14(22)\\[/tex]
[tex]\implies \sf T.S.A._{(Cylinder)} =\: \dfrac{44}{7} \times 14 \times 22\\[/tex]
[tex]\implies \sf T.S.A._{(Cylinder)} =\: \dfrac{44}{7} \times 308\\[/tex]
[tex]\implies \sf T.S.A._{(Cylinder)} =\: \dfrac{44 \times 308}{7}\\[/tex]
[tex]\implies \sf T.S.A._{(Cylinder)} =\: \dfrac{\cancel{13552}}{\cancel{7}}\\[/tex]
[tex]\implies \sf T.S.A._{(Cylinder)} =\: \dfrac{1936}{1}\\[/tex]
[tex]\implies \sf T.S.A._{(Cylinder)} =\: 1936\\[/tex]
[tex]\implies \sf\bold{\underline{T.S.A._{(Cylinder)} =\: 1936\: cm^2}}\\[/tex]
[tex]\therefore[/tex] The total surface area of a closed cylinder is 1936 cm² .