Find the total surface area of a cube, whose volume is 3√3a3 cubic units.
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Find the total surface area of a cube, whose volume is 3√3a3 cubic units.
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Answer:
Volume = edge^3
3√3 = edge^3
edge = √3 units
So
Total surface area = 6*edge^2
= 6*(√3)^2
= 6*3
= 18 sq.units
Step-by-step explanation:
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Verified answer
=Answer:
18 sq.units
Step-by-step explanation:
Given volume of cube = .[tex]3\sqrt{3a } ^{2}[/tex]
Let edge of cube be p.
[tex]p^{3}[/tex]=[tex]3\sqrt{3a } ^{2}[/tex]=([tex]\sqrt{3a}^{3}[/tex])
edge of cube [ p = [tex]\sqrt{30}[/tex]]
∴ Total surface area of cube
=6[tex](\sqrt{3a} )^{2}[/tex]=3 X 6[tex]a^{2}[/tex]
Total surface area of cube
=[tex]18a^{2}[/tex]