Find the two conductive integer sum of whose square is 365.
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Find the two conductive integer sum of whose square is 365.
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Answer:
13, 14 or -13, -14
Step-by-step explanation:
Let the numbers be x, x+1
According to the question
x^2 + (x+1)^2 = 365
x^2 + x^2 + 1 + 2x = 365
2(x^2) + 2x = 364
x^2 + x = 182
x^2 + x - 182 = 0
x^2 + 14x -13x -182 = 0
x(x+14) -13(x+14) = 0
(x-13) (x+14) = 0
=> x = 13, -14
When x = 13, x+1 = 14.
When x = -14, x+1 = -13
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Step-by-step explanation:
Solution: Let the two consecutive Numbers be x and x+1. Note : - 13 *14 = 182 , this is because I write 14x - 13x instead of x , so as to solve the quadratic equation . So the two consecutive positive Integers are 13 and 14
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