find the value of 2*1!+4*2!+6*3!+...+(2n)*n!
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find the value of 2*1!+4*2!+6*3!+...+(2n)*n!
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Answer:
Correct option is D)
i
2
+ i
4
+ i
6
+ ...upto (2n+1) terms
=(−1+1)+(−1+1)+(−1+ .....upto (2n+1))terms ⇒ (odd terms)
=0+0+....−1
=−1
Hence, option D is correct.
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