find the value of 2y^2+19=3y^2-16
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Verified answer
Answer:
y = \pm \: \sqrt{35}
Step-by-step explanation:
solving,
[tex]2y^{2} + 19 = 3 {y}^{2} - 16 \\ 3 {y}^{2} - 2 {y}^{2} = 16 + 19 \\ {y}^{2} = 35 \\ y = \pm \: \sqrt{35} [/tex]
step 1-3y^2-2y^2=19+16
y^2=35
y=√35
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