Find the value of 0 if 3sec20 = 2√3
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Answer:
Θ = 15 DEGREE
Step-by-step explanation:
3 SEC 2Θ = 2√3
SEC 2Θ = 2√3 / 3 = 2/√3
SEC 2Θ = SEC 30
THEREFORE, 2Θ =30
Θ = 30/2 = 15 DEGREE
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