find the value of k for which the system of equation 6 X + k y = 25 and 3 X + y = 1 has no solution ... anybody give the answer
Share
find the value of k for which the system of equation 6 X + k y = 25 and 3 X + y = 1 has no solution ... anybody give the answer
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
We know that the system of equations
a
1
x+b
1
y=c
1
a
2
x+b
2
y=c
2
has no solution, if
a
2
a
1
=
b
2
b
1
=
c
2
c
1
Here, a
1
=3,b
1
=1,c
1
=1,a
2
=2k−1,b
2
=k−1,c
2
=2k+1
So, the given system of equations will have no solution, if
2k−1
3
=
k−1
1
=
2k+1
1
2k−1
3
=
k−1
1
and
k−1
1
=
2k+1
1
Now,
2k−1
3
=
k−1
1
⇒3k−3=2k−1⇒k=2
Clearly, for k=2 we have
k−1
1
=
2k+1
1
Hence, the given system of equations will have no solution, if k=2.
Answer:
hope it helps u unnie
btw unnie how r u hope u are doing good
have a great day borahae