find the value of K if the points A(2,3) B(4,K) C(6,-3) are collinear.
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= 1/2(2(k+3) + 4(-3-3)+6(3-k)=0
= 2k + 6 - 24 + 18 - 6k = 0
= 24-24-4k = 0
= -4k = 0
k = 0.