find the value of p for which one root of the quadratic equation p x square - 14 x + 8 is equal to zero is 6
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find the value of p for which one root of the quadratic equation p x square - 14 x + 8 is equal to zero is 6
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Px2 - 14x + 8 = 0
One root = 6
So, p(6)² - 14(6) + 8 = 0
36p - 84 + 8 = 0
36p - 76 =0
36p = 76
p = 76/36
p = 19/9