Find the value of the polynomial q(x) = 3x^3 – 4x + √8 at x = 2.
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Find the value of the polynomial q(x) = 3x^3 – 4x + √8 at x = 2.
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[tex]3 ({2})^{3} - 4(2) + \sqrt{8} [/tex]
[tex]3 \times 8 - 4 \times 2 + \sqrt{8} [/tex]
[tex]24 - 8 + \sqrt{8} [/tex]
[tex]16 + \sqrt{8} [/tex]
Given:-
x = 2
To find:-
q(x) = 3x^3 – 4x + √8
Answer:-
[tex]\tt {q(2) = 3( {2})^{3} - 4(2) + \sqrt{8}} [/tex]
[tex]\tt {q(2) = 3(8) - 8 + \sqrt{8}} [/tex]
[tex]\tt {q(2) = 16 + \sqrt{8}} [/tex]
[tex]\tt {q(2) = 16 + 2.82}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt\boxed{q(2) = 18.82}[/tex]
∴ The value of q(x) = 3x^3 – 4x + √8 at
x = 2 is 18.82