find the value of x so that -6,x,8are in arithmetic progressions.
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Answer:
Given: (x+2),2x,(2x+3) are three consecutive terms of an AP.
So, difference between two consecutive terms will be same.
2x−(x+2)=(2x+3)−2x
2x−x−2=2x+3−2x
x−2=3
x=2+3=5
The value of x is 5.