Find the volume and surface area of a solid in the form of a right circular cylinder with hemispherical ends whose extreme length is 21 dm and diameter is 2.5 dm.
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Find the volume and surface area of a solid in the form of a right circular cylinder with hemispherical ends whose extreme length is 21 dm and diameter is 2.5 dm.
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Verified answer
Answer:-
a. Volume of cylinder is 103,031.25 cm³.
b. Curved surface area is 16,500 cm².
c. Total surface area is 17,466.25 cm².
Explaination:-
Given:-
Dimensions of right circular cylinder are :–
1. Height (h) = 21 dm = 210cm
2. Diameter of base = 2.5dm = 25cm
3. Radius (r) = 25/2 = 12.5cm
We need to find:-
a. Volume
b. Curved surface area
c. Total surface area
Now we can find all values with the help of respected Formula
a. Volume of cylinder = πr²h
=> π × 12.5² × 210
=>22/7 × 12.5² × 210
=>103,031.25 cm³
b. C.S.A. of cylinder = 2πrh,
=> 2 × 22/7 × 12.5 × 210
=> 44/7 × 2625
=>16,500 cm²
c. T.S.A. of the cylinder = 2πr(r+h)
=> 2 × 22/7 × 12.5 (12.5 + 210)
=> 2 × 3.14 × 12.5 × 222.5
=> 17,466.25 cm²
Hence the required values are :-
a. Volume of cylinder is 103,031.25 cm³.
b. Curved surface area is 16,500 cm².
c. Total surface area is 17,466.25 cm².
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Answer:
Given :
Height (h)=21 dm=210cm
Radius (r) =25/2=12.5cm
Volume
=>¶×12.5²×210
=>22/7×12.5²×210
=>103,031.25 cm³
C. S. A
=>2×22/7×12.5×210
=>44/7×2625
=>16,500 cm²
T. S. A
=>2×22/7×12.5(12.5+210)
=>2×3.14×12.5×222.5
=>17,466.25 cm²