Find the weight of a solid rectangular iron piece of size 50 cm x 40 cm x 10 cm, if 1 cm³of iron weighs 8 gm.
Find the weight of a solid rectangular iron piece of size 50 cm x 40 cm x 10 cm, if 1 cm³of iron weighs 8 gm.
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➾Length = 50 cm
➾Breadth = 40 cm
➾Height = 10 cm
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♦ Volume = 50 cm x 40 cm x 10 cm = 20000 cm³
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♣ Given that,
the weight of 1 cm³ of iron is 8 gm.
The weight of the given piece of iron = 20000 x 8 gm
= 160000 gm
= 160 x 1000 gm
= 160 kg
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The weight of the solid rectangular iron piece is .
Answer:
160 kg
Step-by-step explanation:
solid rectangular iron piece of size 50 cm x 40 cm x 10 cm
volume =50x40x10 cm^3
=20000 cm^3
1 cm³of iron weight = 8 gm.
total weight =20000x 8 gm
=160000 gm
=160 x1000 gm
=160 x 1kg
=160 kg