find the zeroes and find the relation of polynomial 2y²-2√2y-3
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find the zeroes and find the relation of polynomial 2y²-2√2y-3
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Answer:
-1/√2 or 3/√2
Step-by-step explanation:
2y²-2√2y-3=0
2y^2-3√2y+√2y-3=0
√2y(√2y-3)+1(√2y-3)=0
(√2y+1)(√2y-3)=0
then (√2y+1)=0 or (√2y-3)=0
hence y would be either -1/√2 or 3/√2
Hope it helps...
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