find the zeroes of x²+3x-5
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Answer:
find the zeroes of x²+3x-5
Verified answer
hello mate,
[tex] {x}^{2} + 3x - 5[/tex]
[tex]a = 1 \\ b = 3 \\ c = - 5[/tex]
using discriminant formula,
[tex]d = {b }^{2} - 4ac[/tex]
[tex]d = {3}^{2} - 4 \times 1 \times ( - 5) \\ d = 9 + 20 \\ d = 29[/tex]
soo,
[tex]x = \frac{ - b + - \sqrt{d} }{2a} [/tex]
[tex]x = \frac{- 3 + - \sqrt{29} }{2} \\ x = \frac{ - 3 - \sqrt{29} }{2} \: or \: \frac{ - 3 + \sqrt{29} }{2} [/tex]
hope it will help you