find two consecutive even numbers such that, three-fourth of the first exceeds two-fifth of the other by 9
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find two consecutive even numbers such that, three-fourth of the first exceeds two-fifth of the other by 9
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Answer:
Step-by-step explanation:
Solution :-
=> Let, 1 no. be x.
Let, 2 no. be x+9.
=>Now,
=>(3/5)(x) = (x+9)(2/5)
=>3(x) = 2(x) + 18
=>x = 18